Top 6 Examples of "robust-orientation in functional component" in JavaScript
Dive into secure and efficient coding practices with our curated list of the top 10 examples showcasing 'robust-orientation' in functional components in JavaScript. Our advanced machine learning engine meticulously scans each line of code, cross-referencing millions of open source libraries to ensure your implementation is not just functional, but also robust and secure. Elevate your React applications to new heights by mastering the art of handling side effects, API calls, and asynchronous operations with confidence and precision.
export function orientation (point1, point2, point3) {
if (robust) {
const o = robustOrientation([point1.x, point1.y], [point2.x, point2.y], [point3.x, point3.y]);
return o === 0 ? o : -o; // the y-axis is inverted
} else {
// return -((point1.y - point3.y) * (point2.x - point3.x) - (point1.x - point3.x) * (point2.y - point3.y));
return (point2.x - point1.x) * (point3.y - point1.y) - (point2.y - point1.y) * (point3.x - point1.x);
}
}function incrementalConvexHull(points, randomSearch) {
var n = points.length
if(n === 0) {
throw new Error("Must have at least d+1 points")
}
var d = points[0].length
if(n <= d) {
throw new Error("Must input at least d+1 points")
}
//FIXME: This could be degenerate, but need to select d+1 non-coplanar points to bootstrap process
var initialSimplex = points.slice(0, d+1)
//Make sure initial simplex is positively oriented
var o = orient.apply(void 0, initialSimplex)
if(o === 0) {
throw new Error("Input not in general position")
}
var initialCoords = new Array(d+1)
for(var i=0; i<=d; ++i) {
initialCoords[i] = i
}
if(o < 0) {
initialCoords[0] = 1
initialCoords[1] = 0
}
//Create initial topological index, glue pointers together (kind of messy)
var initialCell = new Simplex(initialCoords, new Array(d+1), false)
var boundary = initialCell.adjacent
var list = new Array(d+2)function linearlyIndependent(points, d) {
var nhull = new Array(d+1)
for(var i=0; iproto.degenerate = function() {
var pointList = new Array(this.vertices.length)
for(var i=0; ifunction incrementalConvexHull(points, randomSearch) {
var n = points.length
if(n === 0) {
throw new Error("Must have at least d+1 points")
}
var d = points[0].length
if(n <= d) {
throw new Error("Must input at least d+1 points")
}
//FIXME: This could be degenerate, but need to select d+1 non-coplanar points to bootstrap process
var initialSimplex = points.slice(0, d+1)
//Make sure initial simplex is positively oriented
var o = orient.apply(void 0, initialSimplex)
if(o === 0) {
throw new Error("Input not in general position")
}
var initialCoords = new Array(d+1)
for(var i=0; i<=d; ++i) {
initialCoords[i] = i
}
if(o < 0) {
initialCoords[0] = 1
initialCoords[1] = 0
}
//Create initial topological index, glue pointers together (kind of messy)
var initialCell = new Simplex(initialCoords, new Array(d+1), false)
var boundary = initialCell.adjacent
var list = new Array(d+2)function linearlyIndependent(points, d) {
var nhull = new Array(d+1)
for(var i=0; i